http://lomeo.livejournal.com/ ([identity profile] lomeo.livejournal.com) wrote in [personal profile] deniok 2008-04-03 12:34 pm (UTC)

Первая. Во первых, берём форму

FM=(YG)M,

так как очевидно, что F - рекурсивна. Итак,

FM=(YG)M=G(YG)M
G(YG)M=MF=M(YG)
G = \a b . b a
F = Y(\a b . b a)

Вторая сложнее, сейчас подумаю.

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