http://sassa-nf.livejournal.com/ ([identity profile] sassa-nf.livejournal.com) wrote in [personal profile] deniok 2012-06-28 03:53 pm (UTC)

ну я прочитал задание так, что если можно приписать a->d, то можно приписать c=a->d, а стало быть не подходит под условие второго вопроса.
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